A ball is launched vertically from the ground with an initial velocity of 96ft/sec. How can I find the equation or at least how can I start this problem? Here are some questions related to the problem. a. How long does it take the ball to rise to the maximum height? b. What is the maximum height? c.
Jul 30, 2013 · If a ball is thrown vertically upward with a speed of ninety six feet/s, then its top after t seconds is.....? s = 96t ? 16t2. (a) while the optimal top is reached via the ball, its speed is 0, ds/dt = 0 = ninety six -- 32t giving t = 3 sec so H max = ninety six(3) -- sixteen*3^2 feet = a hundred and forty four feet (b) what's the linked fee of the ball while that's 128 feet above the floor on ...
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Ball A is thrown vertically upward from the top of a 30-m-high-building with an initial velocity of 5 m/s. At the same instant another ball B is thrown upward from the ground with an initial velocity of 20 m/s. Determine the height from the ground and the time at which they pass.

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• if a ball is thrown upward at 40 feet per second from a rooftop 24 feet above the ground, then its height above ground t seconds after it is thrown is given by h= -16t^2+40t+24. rewrite this formula w… read more.
• A ball is thrown vertically upward from the ground. It crosses a point at the height of 25 m twice at an interval of 4 seconds. The ball was thrown with the velocity of. The interval between object pass the same point is 4 sec.

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A ball is launched vertically from the ground with an initial velocity of 96ft/sec. How can I find the equation or at least how can I start this problem? Here are some questions related to the problem. a. How long does it take the ball to rise to the maximum height? b. What is the maximum height? c.

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• A ball is thrown vertically upward from the top of a building 102 feet tall with an initial velocity of 60 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=-16t^2+60t+102 What is the distance of the ball from the ground at time t=0? Set t=0 and plug into formula: s(t)=-16t^2+60t+102 s(0)=-16*0^2+60(0)+102

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2 Objects Thrown Vertically Upwards Upward motion and downward motion are perfectly symmetrical A motion path upward, including speed at every point 11 Example #2 A tennis ball is thrown straight up with an initial velocity of m/s. It is caught at the same distance above the ground from which it was...

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Apr 23, 2013 · A ball is thrown vertically upward from the ground with an initial velocity of 101 ft/sec. Use h=-16t^2+v0t+h0 Determine when the ball will reach its maximum height.

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/questions/a-ball-is-thrown-vertically-upward-from-the-ground-it-crosses-a-point It crosses a point at the height of 25 m twice at an interval of 4 seconds. The ball was thrown with the velocity of5. 244 0.

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...a Ball Thrown Vertically up A ball is thrown vertically upwards with a velocity u from the ground (a) How high will the ball rise ? and (b) how long will it be before the ball hits the ground with an initial speed of 25 m/s; Quadratic function (ball thrown upward), Vertical motion under gravity - ball...

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Sep 10, 2012 · The height y is the integral of v (t): y ( t) = V 0 + V T k ( 1 − e − k t) − V T t. If the time of fall would be the same as t up, the ball would fall back to the ground in 2t up time. Substituting 2t up ln (3/2)) for t in y (t), if you get a positive height, longer time is needed to fall to the ground than to rise to the apex. ehild.

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Would a ball thrown vertically upward on Venus return to the ground sooner or later to a ball thrown with the same velocity on earth and why? Asked by Wiki User. 1 2 3. Answer.

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